8x^2+59x+18=8x

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Solution for 8x^2+59x+18=8x equation:



8x^2+59x+18=8x
We move all terms to the left:
8x^2+59x+18-(8x)=0
We add all the numbers together, and all the variables
8x^2+51x+18=0
a = 8; b = 51; c = +18;
Δ = b2-4ac
Δ = 512-4·8·18
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-45}{2*8}=\frac{-96}{16} =-6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+45}{2*8}=\frac{-6}{16} =-3/8 $

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